If number 62532915a completely divisible by 6, then the largest digit at the place of ‘a’ will be , If number 62532915a completely divisible by 6, then the largest digit at the place of ‘a’ will be

Solution

B. 6

Explanation

 Sum of the digits of 62532915a = 33 +a
A can’t be 5 or 2
 it won’t be divisible by 2
(hence by 6).
A = 8 makes the count 41 which isn’t divisible by 3.
A = 6 makes it divisible by both 2 and 3.